Factor 
We can factor out a common factor
from any number of terms if one exists. Is there a common factor
of all 4 terms in this problem?
Yes, 3 is a common factor of all 4 terms.
Factor out the 3
 We
are not finished. If the 4 terms inside the parenthesis can be factored
by the grouping method we need to continue.
3[x(x - 5) + 2(x - 5)] = 3 (x - 5)(x
+ 2) We always completely factor a problem before we are finished
with the problem.
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